What is the answer to solvefor x,w=-5*3^x+1 ?

The answer to solvefor x,w=-5*3^x+1 is x=(ln(-(w-1)/5))/(ln(3))

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solvefor x,w=-5*3^x+1

solve for

x, w = - 5 \cdot 3^{x} + 1

x = \frac{ln ( - \frac{w - 1}{5} )}{ln ( 3 )}

Solution steps

w = - 5 \cdot 3^{x} + 1

Switch sides

- 5 \cdot 3^{x} + 1 = w

Move

1

to the right side

- 5 \cdot 3^{x} = w - 1

Divide both sides by

- 5

3^{x} = - \frac{w - 1}{5}

Apply exponent rules

x ln (3) = ln (- \frac{w - 1}{5})

Solve

x ln (3) = ln (- \frac{w - 1}{5}) : x = \frac{ln ( - \frac{w - 1}{5} )}{ln ( 3 )}

x = \frac{ln ( - \frac{w - 1}{5} )}{ln ( 3 )}

- 3.73 = - 4 x e^{\frac{- x}{4}}

6^{2 x} - 34 (6^{x}) - 72 = 0

x, y = A e^{- k x}

2 7^{2 t + 1} = (\frac{1}{9})^{t - 1}

5^{x + 2} = 4^{2 x - 1}

What is the answer to solvefor x,w=-5*3^x+1 ?
The answer to solvefor x,w=-5*3^x+1 is x=(ln(-(w-1)/5))/(ln(3))