What is the answer to solvefor x,y=Ae^{-kx} ?

The answer to solvefor x,y=Ae^{-kx} is x=-(ln(y/A))/k

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solvefor x,y=Ae^{-kx}

solve for

x, y = A e^{- k x}

x = - \frac{ln ( \frac{y}{A} )}{k}

Solution steps

y = A e^{- k x}

Switch sides

A e^{- k x} = y

Divide both sides by

A

e^{- k x} = \frac{y}{A}

Apply exponent rules

- k x = ln (\frac{y}{A})

Solve

- k x = ln (\frac{y}{A}) : x = - \frac{ln ( \frac{y}{A} )}{k}

x = - \frac{ln ( \frac{y}{A} )}{k}

2 7^{2 t + 1} = (\frac{1}{9})^{t - 1}

5^{x + 2} = 4^{2 x - 1}

5^{x + 2} = 4^{2 x - 2}

e^{e} - 12 e^{- x} - 1 = 0

5 = 10 (0.8)^{x}

What is the answer to solvefor x,y=Ae^{-kx} ?
The answer to solvefor x,y=Ae^{-kx} is x=-(ln(y/A))/k