What is the answer to 3^{x-2}*2^{x-1}=1125 ?

The answer to 3^{x-2}*2^{x-1}=1125 is x=(ln(1125/2))/(ln(6))+2

Solve for x: 3^{x-2}*2^{x-1}=1125

The solution is x=(ln(1125/2))/(ln(6))+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{x - 2} \cdot 2^{x - 1} = 1125

x = \frac{ln ( \frac{1125}{2} )}{ln ( 6 )} + 2

Decimal Notation

x = 5.53417 \dots

Solution steps

3^{x - 2} \cdot 2^{x - 1} = 1125

Apply exponent rules

(x - 2) ln (6) = ln (\frac{1125}{2})

Solve

(x - 2) ln (6) = ln (\frac{1125}{2}) : x = \frac{ln ( \frac{1125}{2} )}{ln ( 6 )} + 2

x = \frac{ln ( \frac{1125}{2} )}{ln ( 6 )} + 2

4^{x} = (2^{x})^{2}

2^{(x)} + 4 x + 12 = 0

e^{- x} + 3 = 0

3 6^{\frac{1}{2} - 4 x} = 6

2^{5} + 2^{x - 1} = 2^{x}

What is the answer to 3^{x-2}*2^{x-1}=1125 ?
The answer to 3^{x-2}*2^{x-1}=1125 is x=(ln(1125/2))/(ln(6))+2
Solve for x: 3^{x-2}*2^{x-1}=1125
The solution is x=(ln(1125/2))/(ln(6))+2