What is the answer to 12=10^{x+5}-7 ?

The answer to 12=10^{x+5}-7 is x=(ln(19))/(ln(10))-5

Solve for x: 12=10^{x+5}-7

The solution is x=(ln(19))/(ln(10))-5

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12 = 1 0^{x + 5} - 7

x = \frac{ln ( 19 )}{ln ( 10 )} - 5

Decimal Notation

x = - 3.72124 \dots

Solution steps

12 = 1 0^{x + 5} - 7

Switch sides

1 0^{x + 5} - 7 = 12

Move

7

to the right side

1 0^{x + 5} = 19

Apply exponent rules

(x + 5) ln (10) = ln (19)

Solve

(x + 5) ln (10) = ln (19) : x = \frac{ln ( 19 )}{ln ( 10 )} - 5

x = \frac{ln ( 19 )}{ln ( 10 )} - 5

1 2^{x} \cdot 1 2^{4} = 1 2^{8}

(\frac{1}{2})^{x} = 3

2 e^{x} - 3 e^{- 3 x} = 0

9^{5 - 3 x} = (\frac{1}{3})^{x - 1}

2 5^{a - 3} = 125

What is the answer to 12=10^{x+5}-7 ?
The answer to 12=10^{x+5}-7 is x=(ln(19))/(ln(10))-5
Solve for x: 12=10^{x+5}-7
The solution is x=(ln(19))/(ln(10))-5