What is the answer to (1+(0.1)/(12))^{12t}=2 ?

The answer to (1+(0.1)/(12))^{12t}=2 is t=(ln(2))/(12ln(\frac{12.1){12})}

Solve for t: (1+(0.1)/(12))^{12t}=2

The solution is t=(ln(2))/(12ln(\frac{12.1){12})}

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(1 + \frac{0.1}{12})^{12 t} = 2

t = \frac{ln ( 2 )}{12 ln ( \frac{12.1}{12} )}

Decimal Notation

t = 6.96031 \dots

Solution steps

(1 + \frac{0.1}{12})^{12 t} = 2

Apply exponent rules

12 t ln (1 + \frac{0.1}{12}) = ln (2)

Solve

12 t ln (1 + \frac{0.1}{12}) = ln (2) : t = \frac{ln ( 2 )}{12 ln ( \frac{12.1}{12} )}

t = \frac{ln ( 2 )}{12 ln ( \frac{12.1}{12} )}

4^{x - 7} = 2

3^{x} = 4.6

8 \cdot 2^{2 x} + 7 \cdot 2^{x} - 1 = 0

2^{x + 1} + 2^{x + 2} + 2^{x + 3} = 224

3^{x} = 78

What is the answer to (1+(0.1)/(12))^{12t}=2 ?
The answer to (1+(0.1)/(12))^{12t}=2 is t=(ln(2))/(12ln(\frac{12.1){12})}
Solve for t: (1+(0.1)/(12))^{12t}=2
The solution is t=(ln(2))/(12ln(\frac{12.1){12})}