What is the answer to 5^{x+1}=100(3)^x ?

The answer to 5^{x+1}=100(3)^x is x=(ln(20))/(ln(5)-ln(3))

Solve for x: 5^{x+1}=100(3)^x

The solution is x=(ln(20))/(ln(5)-ln(3))

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5^{x + 1} = 100 (3)^{x}

x = \frac{ln ( 20 )}{ln ( 5 ) - ln ( 3 )}

Decimal Notation

x = 5.86449 \dots

Solution steps

5^{x + 1} = 100 (3)^{x}

Apply exponent rules

(x + 1) ln (5) = ln (100) + x ln (3)

Solve

(x + 1) ln (5) = ln (100) + x ln (3) : x = \frac{ln ( 20 )}{ln ( 5 ) - ln ( 3 )}

x = \frac{ln ( 20 )}{ln ( 5 ) - ln ( 3 )}

11 e^{- 4 x} = 21

2 \cdot 3^{x} + 5 = 17

300 \cdot 1 0^{x} = 20 \cdot 2 0^{x}

\frac{1}{4} = e^{- x}

3^{x + 5} = \frac{1}{27}

What is the answer to 5^{x+1}=100(3)^x ?
The answer to 5^{x+1}=100(3)^x is x=(ln(20))/(ln(5)-ln(3))
Solve for x: 5^{x+1}=100(3)^x
The solution is x=(ln(20))/(ln(5)-ln(3))