What is the answer to 4^x(5^{2x})=10 ?

The answer to 4^x(5^{2x})=10 is x=(ln(10))/(2ln(2)(1+2log_{4)(5))}

Solve for x: 4^x(5^{2x})=10

The solution is x=(ln(10))/(2ln(2)(1+2log_{4)(5))}

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4^{x} (5^{2 x}) = 10

x = \frac{ln ( 10 )}{2 ln ( 2 ) ( 1 + 2 lo g _{4} ( 5 ) )}

Decimal Notation

x = 0.5

Solution steps

4^{x} (5^{2 x}) = 10

Apply exponent rules

(x + lo g_{4} (5) \cdot 2 x) ln (4) = ln (10)

Solve

(x + lo g_{4} (5) \cdot 2 x) ln (4) = ln (10) : x = \frac{ln ( 10 )}{2 ln ( 2 ) ( 1 + 2 lo g _{4} ( 5 ) )}

x = \frac{ln ( 10 )}{2 ln ( 2 ) ( 1 + 2 lo g _{4} ( 5 ) )}

850 (1 - e^{- 0.06 t}) = 600

5^{x} - 2 = \frac{62 3 ^{3}}{5 ^{2}}

x^{2 x} + 16 = 8 x^{x}

2^{x} = 2000

e^{8 y} = 2

What is the answer to 4^x(5^{2x})=10 ?
The answer to 4^x(5^{2x})=10 is x=(ln(10))/(2ln(2)(1+2log_{4)(5))}
Solve for x: 4^x(5^{2x})=10
The solution is x=(ln(10))/(2ln(2)(1+2log_{4)(5))}