What is the answer to 2^{y-9}=3 ?

The answer to 2^{y-9}=3 is y=(ln(3))/(ln(2))+9

Solve for y: 2^{y-9}=3

The solution is y=(ln(3))/(ln(2))+9

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2^{y - 9} = 3

y = \frac{ln ( 3 )}{ln ( 2 )} + 9

Decimal Notation

y = 10.58496 \dots

Solution steps

2^{y - 9} = 3

Apply exponent rules

(y - 9) ln (2) = ln (3)

Solve

(y - 9) ln (2) = ln (3) : y = \frac{ln ( 3 )}{ln ( 2 )} + 9

y = \frac{ln ( 3 )}{ln ( 2 )} + 9

64 = 3 2^{x - 5}

2^{2048} = x^{x}

2^{3 x} = 4^{x - 1}

2^{(x + 1)} + 2^{(x - 1)} = 10

x, e^{x + y} - x y = 2 y^{2}

What is the answer to 2^{y-9}=3 ?
The answer to 2^{y-9}=3 is y=(ln(3))/(ln(2))+9
Solve for y: 2^{y-9}=3
The solution is y=(ln(3))/(ln(2))+9