What is the answer to 3^{x+2}*8^{x-1}=30 ?

The answer to 3^{x+2}*8^{x-1}=30 is x=(ln(80/3))/(ln(24))

Solve for x: 3^{x+2}*8^{x-1}=30

The solution is x=(ln(80/3))/(ln(24))

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3^{x + 2} \cdot 8^{x - 1} = 30

x = \frac{ln ( \frac{80}{3} )}{ln ( 24 )}

Decimal Notation

x = 1.03315 \dots

Solution steps

3^{x + 2} \cdot 8^{x - 1} = 30

Apply exponent rules

(x - 1 + 3 + lo g_{3} (8) (x - 1)) ln (3) = ln (30)

Solve

(x - 1 + 3 + lo g_{3} (8) (x - 1)) ln (3) = ln (30) : x = \frac{ln ( \frac{80}{3} )}{ln ( 24 )}

x = \frac{ln ( \frac{80}{3} )}{ln ( 24 )}

1 0^{2 x} - 5 (1 0^{x}) + 6 = 0

200 = 2^{x}

1 6^{x + 2} = 8^{x - 1}

4^{- x + 2} = 3^{2 x - 1}

3^{n + 3} = 9^{n}

What is the answer to 3^{x+2}*8^{x-1}=30 ?
The answer to 3^{x+2}*8^{x-1}=30 is x=(ln(80/3))/(ln(24))
Solve for x: 3^{x+2}*8^{x-1}=30
The solution is x=(ln(80/3))/(ln(24))