What is the answer to 4^{-x+2}=3^{2x-1} ?

The answer to 4^{-x+2}=3^{2x-1} is x=(ln(48))/(2ln(6))

Solve for x: 4^{-x+2}=3^{2x-1}

The solution is x=(ln(48))/(2ln(6))

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4^{- x + 2} = 3^{2 x - 1}

x = \frac{ln ( 48 )}{2 ln ( 6 )}

Decimal Notation

x = 1.08027 \dots

Solution steps

4^{- x + 2} = 3^{2 x - 1}

Apply exponent rules

(- x + 2) ln (4) = (2 x - 1) ln (3)

Solve

(- x + 2) ln (4) = (2 x - 1) ln (3) : x = \frac{ln ( 48 )}{2 ln ( 6 )}

x = \frac{ln ( 48 )}{2 ln ( 6 )}

3^{n + 3} = 9^{n}

7^{n + 2} + 4 9^{n + 1} = 120050

2^{x^{2}} = 4^{\frac{9}{2} x - 9}

1 7^{- 2 x} = 6^{- x - 2}

2 5^{\frac{1}{2} + 2 x} = 5

What is the answer to 4^{-x+2}=3^{2x-1} ?
The answer to 4^{-x+2}=3^{2x-1} is x=(ln(48))/(2ln(6))
Solve for x: 4^{-x+2}=3^{2x-1}
The solution is x=(ln(48))/(2ln(6))