What is the answer to 17^{-2x}=6^{-x-2} ?

The answer to 17^{-2x}=6^{-x-2} is x=(2ln(6))/(2ln(17)-ln(6))

Solve for x: 17^{-2x}=6^{-x-2}

The solution is x=(2ln(6))/(2ln(17)-ln(6))

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1 7^{- 2 x} = 6^{- x - 2}

x = \frac{2 ln ( 6 )}{2 ln ( 17 ) - ln ( 6 )}

Decimal Notation

x = 0.92485 \dots

Solution steps

1 7^{- 2 x} = 6^{- x - 2}

Apply exponent rules

- 2 x ln (17) = (- x - 2) ln (6)

Solve

- 2 x ln (17) = (- x - 2) ln (6) : x = \frac{2 ln ( 6 )}{2 ln ( 17 ) - ln ( 6 )}

x = \frac{2 ln ( 6 )}{2 ln ( 17 ) - ln ( 6 )}

2 5^{\frac{1}{2} + 2 x} = 5

7^{x^{2} - 5 x + 6} = 1

5^{x^{2} - 7 x + 9} = \frac{1}{125}

(\frac{1}{2})^{x^{2 - 3}} = 4

25 = 0.2 5^{x}

What is the answer to 17^{-2x}=6^{-x-2} ?
The answer to 17^{-2x}=6^{-x-2} is x=(2ln(6))/(2ln(17)-ln(6))
Solve for x: 17^{-2x}=6^{-x-2}
The solution is x=(2ln(6))/(2ln(17)-ln(6))