What is the answer to 4^{x-1}=(sqrt(2))^x ?

The answer to 4^{x-1}=(sqrt(2))^x is x= 4/3

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4^{x-1}=(sqrt(2))^x

4^{x - 1} = (2)^{x}

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

4^{x - 1} = (2)^{x}

Apply exponent rules

2 (x - 1) = \frac{1}{2} x

Solve

2 (x - 1) = \frac{1}{2} x : x = \frac{4}{3}

x = \frac{4}{3}

ln (5^{8 x + 5}) = ln (2)

x^{l o g_{2} (x)} = 16

2^{2 x + 3} = 16

90 = 100 - 80 (\frac{39}{40})^{t}

2^{2 x} - 2^{x} - 6 = 0

What is the answer to 4^{x-1}=(sqrt(2))^x ?
The answer to 4^{x-1}=(sqrt(2))^x is x= 4/3
Solve for x: 4^{x-1}=(sqrt(2))^x
The solution is x= 4/3