What is the answer to sqrt(2^{2x+3)}=16 ?

The answer to sqrt(2^{2x+3)}=16 is x= 5/2

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sqrt(2^{2x+3)}=16

2^{2 x + 3} = 16

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

2^{2 x + 3} = 16

Apply exponent rules

(2 x + 3) \frac{1}{2} = 4

Solve

(2 x + 3) \frac{1}{2} = 4 : x = \frac{5}{2}

x = \frac{5}{2}

90 = 100 - 80 (\frac{39}{40})^{t}

2^{2 x} - 2^{x} - 6 = 0

2^{x + 1} + 2^{x + 3} - 40 = 0

6 4^{2^{1 - x}} = 8^{2^{x + 1}}

x^{2} e^{x} - x e^{x} - 2 e^{x} = 0

What is the answer to sqrt(2^{2x+3)}=16 ?
The answer to sqrt(2^{2x+3)}=16 is x= 5/2
Solve for x: sqrt(2^{2x+3)}=16
The solution is x= 5/2