What is the answer to 2^x-4=-4^x+4 ?

The answer to 2^x-4=-4^x+4 is x=(ln((sqrt(33)-1)/2))/(ln(2))

Solve for x: 2^x-4=-4^x+4

The solution is x=(ln((sqrt(33)-1)/2))/(ln(2))

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2^{x} - 4 = - 4^{x} + 4

x = \frac{ln ( \frac{33 - 1}{2} )}{ln ( 2 )}

Decimal Notation

x = 1.24627 \dots

Solution steps

2^{x} - 4 = - 4^{x} + 4

Apply exponent rules

2^{x} - 4 = - (2^{x})^{2} + 4

Rewrite the equation with

2^{x} = u

u - 4 = - (u)^{2} + 4

Solve

u - 4 = - u^{2} + 4 : u = - \frac{1 + 33}{2}, u = \frac{33 - 1}{2}

u = - \frac{1 + 33}{2}, u = \frac{33 - 1}{2}

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = - \frac{1 + 33}{2} :

No Solution for

x \in R

Solve

2^{x} = \frac{33 - 1}{2} : x = \frac{ln ( \frac{33 - 1}{2} )}{ln ( 2 )}

x = \frac{ln ( \frac{33 - 1}{2} )}{ln ( 2 )}

x, 3^{2 x + 1} + 1 = 3^{x}

43 = 3 (7)^{x}

4^{p} - 4^{p - 1} = 6

x, x e^{y} + y e^{x} = 1

8^{x - 5} = 1024

What is the answer to 2^x-4=-4^x+4 ?
The answer to 2^x-4=-4^x+4 is x=(ln((sqrt(33)-1)/2))/(ln(2))
Solve for x: 2^x-4=-4^x+4
The solution is x=(ln((sqrt(33)-1)/2))/(ln(2))