What is the answer to solvefor x,3^{2x+1}+1=3^x ?

The answer to solvefor x,3^{2x+1}+1=3^x is No Solution for x\in\mathbb{R}

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solvefor x,3^{2x+1}+1=3^x

solve for

x, 3^{2 x + 1} + 1 = 3^{x}

No Solution for x \in R

Solution steps

3^{2 x + 1} + 1 = 3^{x}

Apply exponent rules

(3^{x})^{2} \cdot 3^{1} + 1 = 3^{x}

Rewrite the equation with

3^{x} = u

(u)^{2} \cdot 3^{1} + 1 = u

Solve

u^{2} \cdot 3^{1} + 1 = u :

No Solution for

u \in R

No Solution for x \in R

43 = 3 (7)^{x}

4^{p} - 4^{p - 1} = 6

x, x e^{y} + y e^{x} = 1

8^{x - 5} = 1024

2 7^{4 x} = 9^{x + 1}

What is the answer to solvefor x,3^{2x+1}+1=3^x ?
The answer to solvefor x,3^{2x+1}+1=3^x is No Solution for x\in\mathbb{R}