What is the answer to 12^{m+3}=(1/3)^{2m} ?

The answer to 12^{m+3}=(1/3)^{2m} is m=-(3ln(12))/(ln(108))

Solve for m: 12^{m+3}=(1/3)^{2m}

The solution is m=-(3ln(12))/(ln(108))

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1 2^{m + 3} = (\frac{1}{3})^{2 m}

m = - \frac{3 ln ( 12 )}{ln ( 108 )}

Decimal Notation

m = - 1.59216 \dots

Solution steps

1 2^{m + 3} = (\frac{1}{3})^{2 m}

Apply exponent rules

(m + 3) ln (12) = 2 m ln (\frac{1}{3})

Solve

(m + 3) ln (12) = 2 m ln (\frac{1}{3}) : m = - \frac{3 ln ( 12 )}{ln ( 108 )}

m = - \frac{3 ln ( 12 )}{ln ( 108 )}

3^{2 x - 8} = 81

5^{x + 2} + 3 \cdot 5^{x + 1} - 8 = 0

0.6 4^{- 5 x + 1} = 0.51 2^{- 5 x + 4}

16 = 8^{x}

2 x e^{- x} + (- e^{- x}) x^{2} = 0

What is the answer to 12^{m+3}=(1/3)^{2m} ?
The answer to 12^{m+3}=(1/3)^{2m} is m=-(3ln(12))/(ln(108))
Solve for m: 12^{m+3}=(1/3)^{2m}
The solution is m=-(3ln(12))/(ln(108))