What is the answer to 0.64^{-5x+1}=0.512^{-5x+4} ?

The answer to 0.64^{-5x+1}=0.512^{-5x+4} is x=-(ln(0.64)-4ln(0.512))/(5(ln(0.512)-ln(0.64)))

Solve for x: 0.64^{-5x+1}=0.512^{-5x+4}

The solution is x=-(ln(0.64)-4ln(0.512))/(5(ln(0.512)-ln(0.64)))

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0.6 4^{- 5 x + 1} = 0.51 2^{- 5 x + 4}

x = - \frac{ln ( 0.64 ) - 4 ln ( 0.512 )}{5 ( ln ( 0.512 ) - ln ( 0.64 ) )}

Decimal Notation

x = 2

Solution steps

0.6 4^{- 5 x + 1} = 0.51 2^{- 5 x + 4}

Apply exponent rules

(- 5 x + 1) ln (0.64) = (- 5 x + 4) ln (0.512)

Solve

(- 5 x + 1) ln (0.64) = (- 5 x + 4) ln (0.512) : x = - \frac{ln ( 0.64 ) - 4 ln ( 0.512 )}{5 ( ln ( 0.512 ) - ln ( 0.64 ) )}

x = - \frac{ln ( 0.64 ) - 4 ln ( 0.512 )}{5 ( ln ( 0.512 ) - ln ( 0.64 ) )}

16 = 8^{x}

2 x e^{- x} + (- e^{- x}) x^{2} = 0

1 0^{\frac{x}{3}} = 20

3^{x + 1} + 3^{x + 2} + 3^{x + 3} = 351

70 = 16 + 72 \cdot e^{- 175 t}

What is the answer to 0.64^{-5x+1}=0.512^{-5x+4} ?
The answer to 0.64^{-5x+1}=0.512^{-5x+4} is x=-(ln(0.64)-4ln(0.512))/(5(ln(0.512)-ln(0.64)))
Solve for x: 0.64^{-5x+1}=0.512^{-5x+4}
The solution is x=-(ln(0.64)-4ln(0.512))/(5(ln(0.512)-ln(0.64)))