What is the answer to 3^{x+1}+3^{x+2}+3^{x+3}=351 ?

The answer to 3^{x+1}+3^{x+2}+3^{x+3}=351 is x=2

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3^{x+1}+3^{x+2}+3^{x+3}=351

3^{x + 1} + 3^{x + 2} + 3^{x + 3} = 351

x = 2

Solution steps

3^{x + 1} + 3^{x + 2} + 3^{x + 3} = 351

Factor

3^{x + 1} + 3^{x + 2} + 3^{x + 3} : 13 \cdot 3^{x + 1}

13 \cdot 3^{x + 1} = 351

Divide both sides by

13

3^{x + 1} = 27

Apply exponent rules

x + 1 = 3

Solve

x + 1 = 3 : x = 2

x = 2

70 = 16 + 72 \cdot e^{- 175 t}

1 0^{3 x - 2} = 13

2 e^{2 x} = 1

2 7^{x} = \frac{9 ^{2 x - 1}}{3 ^{x}}

312 5^{x - 4} = 62 5^{x + 3}

What is the answer to 3^{x+1}+3^{x+2}+3^{x+3}=351 ?
The answer to 3^{x+1}+3^{x+2}+3^{x+3}=351 is x=2
Solve for x: 3^{x+1}+3^{x+2}+3^{x+3}=351
The solution is x=2