What is the answer to 4*8^{x-1}=3*5^{2x+1} ?

The answer to 4*8^{x-1}=3*5^{2x+1} is x=(ln(30))/(3ln(2)-2ln(5))

Solve for x: 4*8^{x-1}=3*5^{2x+1}

The solution is x=(ln(30))/(3ln(2)-2ln(5))

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4 \cdot 8^{x - 1} = 3 \cdot 5^{2 x + 1}

x = \frac{ln ( 30 )}{3 ln ( 2 ) - 2 ln ( 5 )}

Decimal Notation

x = - 2.98498 \dots

Solution steps

4 \cdot 8^{x - 1} = 3 \cdot 5^{2 x + 1}

Apply exponent rules

ln (4) + (x - 1) ln (8) = ln (3) + (2 x + 1) ln (5)

Solve

ln (4) + (x - 1) ln (8) = ln (3) + (2 x + 1) ln (5) : x = \frac{ln ( 30 )}{3 ln ( 2 ) - 2 ln ( 5 )}

x = \frac{ln ( 30 )}{3 ln ( 2 ) - 2 ln ( 5 )}

2^{x - 3} = 6

2^{x - 3} = 7

70 = 120 e^{2 k} + 25

2 e^{- x} x - e^{- x} (x^{2} - 3) = 0

0 = e^{x} - 4

What is the answer to 4*8^{x-1}=3*5^{2x+1} ?
The answer to 4*8^{x-1}=3*5^{2x+1} is x=(ln(30))/(3ln(2)-2ln(5))
Solve for x: 4*8^{x-1}=3*5^{2x+1}
The solution is x=(ln(30))/(3ln(2)-2ln(5))