What is the answer to 81^{5x}=27^{x+2} ?

The answer to 81^{5x}=27^{x+2} is x= 6/17

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81^{5x}=27^{x+2}

8 1^{5 x} = 2 7^{x + 2}

x = \frac{6}{17}

Decimal Notation

x = 0.35294 \dots

Solution steps

8 1^{5 x} = 2 7^{x + 2}

Apply exponent rules

20 x = 3 (x + 2)

Solve

20 x = 3 (x + 2) : x = \frac{6}{17}

x = \frac{6}{17}

6 \cdot 2^{4 x} = 21

e^{2 x} - 4 e^{x} - 21 = 0

3^{(4 - x)} = 2 7^{(2 - x)}

y, x^{y} = N

3^{x - 2} = 11

What is the answer to 81^{5x}=27^{x+2} ?
The answer to 81^{5x}=27^{x+2} is x= 6/17
Solve for x: 81^{5x}=27^{x+2}
The solution is x= 6/17