What is the answer to 8^{5x}= 1/(16^{4x+2)} ?

The answer to 8^{5x}= 1/(16^{4x+2)} is x=-8/31

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8^{5x}= 1/(16^{4x+2)}

8^{5 x} = \frac{1}{1 6 ^{4 x + 2}}

x = - \frac{8}{31}

Decimal Notation

x = - 0.25806 \dots

Solution steps

8^{5 x} = \frac{1}{1 6 ^{4 x + 2}}

Apply exponent rules

15 x = 4 (- 4 x - 2)

Solve

15 x = 4 (- 4 x - 2) : x = - \frac{8}{31}

x = - \frac{8}{31}

Verify Solutions:

x = - \frac{8}{31}

True

The solution is

x = - \frac{8}{31}

11.5 = 25 - 20 e^{- \frac{6 t}{50}}

R (3.3) = R (0) e^{- k (3.3)}

e^{2 - 3 x} = 5 - 3 x

2^{x} + 2^{x + 1} = 6

100 = 24 e^{5 k}

What is the answer to 8^{5x}= 1/(16^{4x+2)} ?
The answer to 8^{5x}= 1/(16^{4x+2)} is x=-8/31
Solve for x: 8^{5x}= 1/(16^{4x+2)}
The solution is x=-8/31