What is the answer to R(3.3)=R(0)e^{-k(3.3)} ?

The answer to R(3.3)=R(0)e^{-k(3.3)} is k=-(ln(\frac{R(3.3))/(R(0)))}{3.3}

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R(3.3)=R(0)e^{-k(3.3)}

R (3.3) = R (0) e^{- k (3.3)}

k = - \frac{ln ( \frac{R ( 3.3 )}{R ( 0 )} )}{3.3}

Solution steps

R (3.3) = R (0) e^{- k (3.3)}

Switch sides

R (0) e^{- k 3.3} = R (3.3)

Divide both sides by

R (0)

e^{- k 3.3} = \frac{R ( 3.3 )}{R ( 0 )}

Apply exponent rules

- k \cdot 3.3 = ln (\frac{R ( 3.3 )}{R ( 0 )})

Solve

- k \cdot 3.3 = ln (\frac{R ( 3.3 )}{R ( 0 )}) : k = - \frac{ln ( \frac{R ( 3.3 )}{R ( 0 )} )}{3.3}

k = - \frac{ln ( \frac{R ( 3.3 )}{R ( 0 )} )}{3.3}

e^{2 - 3 x} = 5 - 3 x

2^{x} + 2^{x + 1} = 6

100 = 24 e^{5 k}

45000000 = 25700000 \cdot 1. 7^{t}

1 6^{- n} = (\frac{1}{4})^{3 n + 1}

What is the answer to R(3.3)=R(0)e^{-k(3.3)} ?
The answer to R(3.3)=R(0)e^{-k(3.3)} is k=-(ln(\frac{R(3.3))/(R(0)))}{3.3}