What is the answer to 16^{-n}=(1/4)^{3n+1} ?

The answer to 16^{-n}=(1/4)^{3n+1} is n=-1

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16^{-n}=(1/4)^{3n+1}

1 6^{- n} = (\frac{1}{4})^{3 n + 1}

n = - 1

Solution steps

1 6^{- n} = (\frac{1}{4})^{3 n + 1}

Apply exponent rules

- 2 n = - (3 n + 1)

Solve

- 2 n = - (3 n + 1) : n = - 1

n = - 1

\frac{1}{5 ^{- 3 x}} = 2 5^{x - 1}

7^{g} = 14

(\frac{5}{7})^{x} = 1

6^{x + 3} = 17

1 0^{x - 3} = 2^{10 + x}

What is the answer to 16^{-n}=(1/4)^{3n+1} ?
The answer to 16^{-n}=(1/4)^{3n+1} is n=-1
Solve for n: 16^{-n}=(1/4)^{3n+1}
The solution is n=-1