What is the answer to 10^{x-3}=2^{10+x} ?

The answer to 10^{x-3}=2^{10+x} is x=(10ln(2)+3ln(10))/(ln(5))

Solve for x: 10^{x-3}=2^{10+x}

The solution is x=(10ln(2)+3ln(10))/(ln(5))

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1 0^{x - 3} = 2^{10 + x}

x = \frac{10 ln ( 2 ) + 3 ln ( 10 )}{ln ( 5 )}

Decimal Notation

x = 8.59879 \dots

Solution steps

1 0^{x - 3} = 2^{10 + x}

Apply exponent rules

(x - 3) ln (10) = (10 + x) ln (2)

Solve

(x - 3) ln (10) = (10 + x) ln (2) : x = \frac{10 ln ( 2 ) + 3 ln ( 10 )}{ln ( 5 )}

x = \frac{10 ln ( 2 ) + 3 ln ( 10 )}{ln ( 5 )}

6^{x + 3} = 36

3^{2 x} = 2 7^{4}

2^{2 x - 1} = 3^{x}

x, 4^{2 x} = 8^{x} (2)

9^{x^{2} + 2} = 2 7^{2 x}

What is the answer to 10^{x-3}=2^{10+x} ?
The answer to 10^{x-3}=2^{10+x} is x=(10ln(2)+3ln(10))/(ln(5))
Solve for x: 10^{x-3}=2^{10+x}
The solution is x=(10ln(2)+3ln(10))/(ln(5))