What is the answer to 2(2^{2x})-6(2^x)+4=0 ?

The answer to 2(2^{2x})-6(2^x)+4=0 is x=1,x=0

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2(2^{2x})-6(2^x)+4=0

2 (2^{2 x}) - 6 (2^{x}) + 4 = 0

x = 1, x = 0

Solution steps

2 (2^{2 x}) - 6 (2^{x}) + 4 = 0

Apply exponent rules

(2^{x})^{2} \cdot 2^{1} - 6 \cdot 2^{x} + 4 = 0

Rewrite the equation with

2^{x} = u

(u)^{2} \cdot 2^{1} - 6 u + 4 = 0

Solve

u^{2} \cdot 2^{1} - 6 u + 4 = 0 : u = 2, u = 1

u = 2, u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 2 : x = 1

Solve

2^{x} = 1 : x = 0

x = 1, x = 0

12 = 200 (1 - e^{- \frac{t}{800}})

3^{(x + 1)} = 2^{3 x}

e^{l n (6 x)} = 19

(\frac{3}{4})^{x} = \frac{16}{9}

2^{x} + 2^{x + 3} = 48

What is the answer to 2(2^{2x})-6(2^x)+4=0 ?
The answer to 2(2^{2x})-6(2^x)+4=0 is x=1,x=0
Solve for x: 2(2^{2x})-6(2^x)+4=0
The solution is x=1,x=0