What is the answer to (-9)^{(1-2x)}=3^{-4} ?

The answer to (-9)^{(1-2x)}=3^{-4} is x= 3/2

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(-9)^{(1-2x)}=3^{-4}

(- 9)^{(1 - 2 x)} = 3^{- 4}

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

(- 9)^{(1 - 2 x)} = 3^{- 4}

(- a)^{n} = b,

assuming

n

is even, solve

a^{n} = b

instead

Solve

9^{1 - 2 x} = 3^{- 4} : x = \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

True

The solution is

x = \frac{3}{2}

8^{x + 3} = 3 2^{3 x}

7^{z^{2} + 4} = 7^{- 4 z}

x^{x} = 31

2^{3 x - 1} - 2^{2 x - 1} = 2^{x + 3} - 2

e^{3 x} = \frac{1}{8}

What is the answer to (-9)^{(1-2x)}=3^{-4} ?
The answer to (-9)^{(1-2x)}=3^{-4} is x= 3/2
Solve for x: (-9)^{(1-2x)}=3^{-4}
The solution is x= 3/2