What is the answer to 3(4^x)=(2)^{3x-5} ?

The answer to 3(4^x)=(2)^{3x-5} is x=(ln(96))/(ln(2))

Solve for x: 3(4^x)=(2)^{3x-5}

The solution is x=(ln(96))/(ln(2))

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3 (4^{x}) = (2)^{3 x - 5}

x = \frac{ln ( 96 )}{ln ( 2 )}

Decimal Notation

x = 6.58496 \dots

Solution steps

3 (4^{x}) = (2)^{3 x - 5}

Apply exponent rules

ln (3) + 2 x ln (2) = (3 x - 5) ln (2)

Solve

ln (3) + 2 x ln (2) = (3 x - 5) ln (2) : x = \frac{ln ( 96 )}{ln ( 2 )}

x = \frac{ln ( 96 )}{ln ( 2 )}

0. 5^{\frac{9900}{x}} = 30

3 \cdot 5^{(x + 1)} = 7 \cdot 4^{x}

3^{4 x} = 2 7^{x + 3}

27.5 = 55 e^{- 0.0036 t}

4^{5 x - 2} = \frac{1}{4 ^{6}}

What is the answer to 3(4^x)=(2)^{3x-5} ?
The answer to 3(4^x)=(2)^{3x-5} is x=(ln(96))/(ln(2))
Solve for x: 3(4^x)=(2)^{3x-5}
The solution is x=(ln(96))/(ln(2))