What is the answer to 2^{x+1}=16^{x-4} ?

The answer to 2^{x+1}=16^{x-4} is x= 17/3

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2^{x+1}=16^{x-4}

2^{x + 1} = 1 6^{x - 4}

x = \frac{17}{3}

Decimal Notation

x = 5.66666 \dots

Solution steps

2^{x + 1} = 1 6^{x - 4}

Apply exponent rules

x + 1 = 4 (x - 4)

Solve

x + 1 = 4 (x - 4) : x = \frac{17}{3}

x = \frac{17}{3}

\frac{6 e ^{x}}{( 6 + e ^{x} ) ^{2}} = 0

4^{x + 1} = 3

1 2^{x - 2} = 20

4 9^{x} - 8 \cdot 7^{x} + 7 = 0

0.9765625 = 500 (2)^{n - 1}

What is the answer to 2^{x+1}=16^{x-4} ?
The answer to 2^{x+1}=16^{x-4} is x= 17/3
Solve for x: 2^{x+1}=16^{x-4}
The solution is x= 17/3