What is the answer to 2^{3-x}=565 ?

The answer to 2^{3-x}=565 is x=-(ln(565)-3ln(2))/(ln(2))

Solve for x: 2^{3-x}=565

The solution is x=-(ln(565)-3ln(2))/(ln(2))

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2^{3 - x} = 565

x = - \frac{ln ( 565 ) - 3 ln ( 2 )}{ln ( 2 )}

Decimal Notation

x = - 6.14210 \dots

Solution steps

2^{3 - x} = 565

Apply exponent rules

(3 - x) ln (2) = ln (565)

Solve

(3 - x) ln (2) = ln (565) : x = - \frac{ln ( 565 ) - 3 ln ( 2 )}{ln ( 2 )}

x = - \frac{ln ( 565 ) - 3 ln ( 2 )}{ln ( 2 )}

x, 2^{x} = \frac{1}{2}

4 e^{x - 2} = 91

2^{x - 4} = 3^{2 x - 1}

3^{x + 1} + 3^{x} + 3^{x + 2} = 117

7^{x + 1} = 343

What is the answer to 2^{3-x}=565 ?
The answer to 2^{3-x}=565 is x=-(ln(565)-3ln(2))/(ln(2))
Solve for x: 2^{3-x}=565
The solution is x=-(ln(565)-3ln(2))/(ln(2))