What is the answer to 4^{x+3}=16^{x^2-2x} ?

The answer to 4^{x+3}=16^{x^2-2x} is x=3,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4^{x+3}=16^{x^2-2x}

4^{x + 3} = 1 6^{x^{2} - 2 x}

x = 3, x = - \frac{1}{2}

Decimal Notation

x = 3, x = - 0.5

Solution steps

4^{x + 3} = 1 6^{x^{2} - 2 x}

Apply exponent rules

x + 3 = 2 (x^{2} - 2 x)

Solve

x + 3 = 2 (x^{2} - 2 x) : x = 3, x = - \frac{1}{2}

x = 3, x = - \frac{1}{2}

12 8^{x} = 4 \cdot 2^{x}

e^{2 x} = e^{x^{2} - 8}

y, e^{- x^{2} - y^{2}} = c

\frac{1}{4} = 4^{x}

3^{x + 4} = 6^{x}

What is the answer to 4^{x+3}=16^{x^2-2x} ?
The answer to 4^{x+3}=16^{x^2-2x} is x=3,x=-1/2
Solve for x: 4^{x+3}=16^{x^2-2x}
The solution is x=3,x=-1/2