What is the answer to solvefor y,e^{-x^2-y^2}=c ?

The answer to solvefor y,e^{-x^2-y^2}=c is y=sqrt(-ln(c)-x^2),y=-sqrt(-ln(c)-x^2)

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solvefor y,e^{-x^2-y^2}=c

solve for

y, e^{- x^{2} - y^{2}} = c

y = - ln (c) - x^{2}, y = - - ln (c) - x^{2}

Solution steps

e^{- x^{2} - y^{2}} = c

Apply exponent rules

- x^{2} - y^{2} = ln (c)

Solve

- x^{2} - y^{2} = ln (c) : y = - ln (c) - x^{2}, y = - - ln (c) - x^{2}

y = - ln (c) - x^{2}, y = - - ln (c) - x^{2}

\frac{1}{4} = 4^{x}

3^{x + 4} = 6^{x}

5^{2 x} - 5^{x} = 20

2 = (1 + 0.1)^{t}

3 6^{4} = 6^{3 x + 2}

What is the answer to solvefor y,e^{-x^2-y^2}=c ?
The answer to solvefor y,e^{-x^2-y^2}=c is y=sqrt(-ln(c)-x^2),y=-sqrt(-ln(c)-x^2)