What is the answer to 4^{y+1}=6 ?

The answer to 4^{y+1}=6 is y=(ln(6))/(2ln(2))-1

Solve for y: 4^{y+1}=6

The solution is y=(ln(6))/(2ln(2))-1

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4^{y + 1} = 6

y = \frac{ln ( 6 )}{2 ln ( 2 )} - 1

Decimal Notation

y = 0.29248 \dots

Solution steps

4^{y + 1} = 6

Apply exponent rules

(y + 1) ln (4) = ln (6)

Solve

(y + 1) ln (4) = ln (6) : y = \frac{ln ( 6 )}{2 ln ( 2 )} - 1

y = \frac{ln ( 6 )}{2 ln ( 2 )} - 1

2 = e^{0.08 t}

e^{x} = 1000000000

55 = 3 1^{x}

4^{x} + 4^{- x} = 7

n = 10 (2)^{n - 1}

What is the answer to 4^{y+1}=6 ?
The answer to 4^{y+1}=6 is y=(ln(6))/(2ln(2))-1
Solve for y: 4^{y+1}=6
The solution is y=(ln(6))/(2ln(2))-1