What is the answer to 55=31^x ?

The answer to 55=31^x is x=(ln(55))/(ln(31))

The solution is x=(ln(55))/(ln(31))

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55=31^x

55 = 3 1^{x}

x = \frac{ln ( 55 )}{ln ( 31 )}

Decimal Notation

x = 1.16696 \dots

Solution steps

55 = 3 1^{x}

Apply exponent rules

ln (55) = x ln (31)

Solve

ln (55) = x ln (31) : x = \frac{ln ( 55 )}{ln ( 31 )}

x = \frac{ln ( 55 )}{ln ( 31 )}

4^{x} + 4^{- x} = 7

n = 10 (2)^{n - 1}

3^{x} \cdot 4^{(2 x + 1)} = 6^{x + 2}

e^{- 2 x} - 3 e^{- x} = - 2

100000 = 50000 \cdot (1 + 0.04)^{n}