What is the answer to 68^x=22 ?

The answer to 68^x=22 is x=(ln(22))/(ln(68))

The solution is x=(ln(22))/(ln(68))

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68^x=22

6 8^{x} = 22

x = \frac{ln ( 22 )}{ln ( 68 )}

Decimal Notation

x = 0.73255 \dots

Solution steps

6 8^{x} = 22

Apply exponent rules

x ln (68) = ln (22)

Solve

x ln (68) = ln (22) : x = \frac{ln ( 22 )}{ln ( 68 )}

x = \frac{ln ( 22 )}{ln ( 68 )}

34 \cdot 1.12 5^{t} = 143

x, 2^{x - 5} = 5

180 = 16.56 (1.078)^{t} + 97

2^{x - 4} = 3

e^{x} x^{2} - 2 e^{x} = 0