What is the answer to 2^{x-1}=20 ?

The answer to 2^{x-1}=20 is x=(ln(20))/(ln(2))+1

Solve for x: 2^{x-1}=20

The solution is x=(ln(20))/(ln(2))+1

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2^{x - 1} = 20

x = \frac{ln ( 20 )}{ln ( 2 )} + 1

Decimal Notation

x = 5.32192 \dots

Solution steps

2^{x - 1} = 20

Apply exponent rules

(x - 1) ln (2) = ln (20)

Solve

(x - 1) ln (2) = ln (20) : x = \frac{ln ( 20 )}{ln ( 2 )} + 1

x = \frac{ln ( 20 )}{ln ( 2 )} + 1

7^{x} = - 1

2 5^{2 x + 3} = 12 5^{2 x + 8}

2^{x - 1} = 64

4^{3 x + 6} = 1

6^{2 x - 3} = 7^{3 - 2 x}

What is the answer to 2^{x-1}=20 ?
The answer to 2^{x-1}=20 is x=(ln(20))/(ln(2))+1
Solve for x: 2^{x-1}=20
The solution is x=(ln(20))/(ln(2))+1