What is the answer to 6^{2x-3}=7^{3-2x} ?

The answer to 6^{2x-3}=7^{3-2x} is x=(3ln(7)+3ln(6))/(2ln(42))

Solve for x: 6^{2x-3}=7^{3-2x}

The solution is x=(3ln(7)+3ln(6))/(2ln(42))

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6^{2 x - 3} = 7^{3 - 2 x}

x = \frac{3 ln ( 7 ) + 3 ln ( 6 )}{2 ln ( 42 )}

Decimal Notation

x = 1.5

Solution steps

6^{2 x - 3} = 7^{3 - 2 x}

Apply exponent rules

(2 x - 3) ln (6) = (3 - 2 x) ln (7)

Solve

(2 x - 3) ln (6) = (3 - 2 x) ln (7) : x = \frac{3 ln ( 7 ) + 3 ln ( 6 )}{2 ln ( 42 )}

x = \frac{3 ln ( 7 ) + 3 ln ( 6 )}{2 ln ( 42 )}

8^{5 x + 8} = 3

e^{6 x} - e^{x} = 0

2^{2 x - 3} = 5^{1 - x}

5^{x - 1} = 8^{x + 1}

9^{X} - 6 \cdot 3^{X} - 81 = 0

What is the answer to 6^{2x-3}=7^{3-2x} ?
The answer to 6^{2x-3}=7^{3-2x} is x=(3ln(7)+3ln(6))/(2ln(42))
Solve for x: 6^{2x-3}=7^{3-2x}
The solution is x=(3ln(7)+3ln(6))/(2ln(42))