What is the answer to 18^{2x-3}=20^{x+1} ?

The answer to 18^{2x-3}=20^{x+1} is x=(ln(20)+3ln(18))/(ln(81/5))

Solve for x: 18^{2x-3}=20^{x+1}

The solution is x=(ln(20)+3ln(18))/(ln(81/5))

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1 8^{2 x - 3} = 2 0^{x + 1}

x = \frac{ln ( 20 ) + 3 ln ( 18 )}{ln ( \frac{81}{5} )}

Decimal Notation

x = 4.18915 \dots

Solution steps

1 8^{2 x - 3} = 2 0^{x + 1}

Apply exponent rules

(2 x - 3) ln (18) = (x + 1) ln (20)

Solve

(2 x - 3) ln (18) = (x + 1) ln (20) : x = \frac{ln ( 20 ) + 3 ln ( 18 )}{ln ( \frac{81}{5} )}

x = \frac{ln ( 20 ) + 3 ln ( 18 )}{ln ( \frac{81}{5} )}

\frac{2 ^{x - 3}}{4 ^{1 - x}} = 1

625 (5^{x - 2}) - 5^{x} = 120

12 \cdot 1.1 7^{t} = 56

5 = 8^{x}

e^{x} + e^{- x} = 2 e

What is the answer to 18^{2x-3}=20^{x+1} ?
The answer to 18^{2x-3}=20^{x+1} is x=(ln(20)+3ln(18))/(ln(81/5))
Solve for x: 18^{2x-3}=20^{x+1}
The solution is x=(ln(20)+3ln(18))/(ln(81/5))