What is the answer to 4(3^x)=20 ?

The answer to 4(3^x)=20 is x=(ln(5))/(ln(3))

Solve for x: 4(3^x)=20

The solution is x=(ln(5))/(ln(3))

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4 (3^{x}) = 20

x = \frac{ln ( 5 )}{ln ( 3 )}

Decimal Notation

x = 1.46497 \dots

Solution steps

4 (3^{x}) = 20

Divide both sides by

4

3^{x} = 5

Apply exponent rules

x ln (3) = ln (5)

Solve

x ln (3) = ln (5) : x = \frac{ln ( 5 )}{ln ( 3 )}

x = \frac{ln ( 5 )}{ln ( 3 )}

2 5^{x} - 16 = 0

93 = 3 5^{x}

t, e^{k t} = \frac{1}{11}

3^{5 x + 8} = 7^{2 x - 4}

4 - 2 e^{x + 1} = - 12