What is the answer to 2(1+0.1275)^x=(1+0.1375)^x ?

The answer to 2(1+0.1275)^x=(1+0.1375)^x is x=(ln(2))/(ln(1.1375)-ln(1.1275))

Solve for x: 2(1+0.1275)^x=(1+0.1375)^x

The solution is x=(ln(2))/(ln(1.1375)-ln(1.1275))

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2 (1 + 0.1275)^{x} = (1 + 0.1375)^{x}

x = \frac{ln ( 2 )}{ln ( 1.1375 ) - ln ( 1.1275 )}

Decimal Notation

x = 78.49840 \dots

Solution steps

2 (1 + 0.1275)^{x} = (1 + 0.1375)^{x}

Apply exponent rules

ln (2) + x ln (1 + 0.1275) = x ln (1 + 0.1375)

Solve

ln (2) + x ln (1 + 0.1275) = x ln (1 + 0.1375) : x = \frac{ln ( 2 )}{ln ( 1.1375 ) - ln ( 1.1275 )}

x = \frac{ln ( 2 )}{ln ( 1.1375 ) - ln ( 1.1275 )}

2^{x} + 2^{x} = 2^{x + 1}

5^{x + 1} = 3^{x + 2}

1 5^{- x + 2} = 1 1^{- 7 x}

9 = 2^{t}

1 8^{x} = 3

What is the answer to 2(1+0.1275)^x=(1+0.1375)^x ?
The answer to 2(1+0.1275)^x=(1+0.1375)^x is x=(ln(2))/(ln(1.1375)-ln(1.1275))
Solve for x: 2(1+0.1275)^x=(1+0.1375)^x
The solution is x=(ln(2))/(ln(1.1375)-ln(1.1275))