What is the answer to 7^{x+6}=3^x ?

The answer to 7^{x+6}=3^x is x=-(6ln(7))/(ln(7)-ln(3))

Solve for x: 7^{x+6}=3^x

The solution is x=-(6ln(7))/(ln(7)-ln(3))

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7^{x + 6} = 3^{x}

x = - \frac{6 ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

Decimal Notation

x = - 13.77964 \dots

Solution steps

7^{x + 6} = 3^{x}

Apply exponent rules

(x + 6) ln (7) = x ln (3)

Solve

(x + 6) ln (7) = x ln (3) : x = - \frac{6 ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

x = - \frac{6 ln ( 7 )}{ln ( 7 ) - ln ( 3 )}

4^{3 x + 5} = 9

7^{x - 1} = e^{x}

e^{7 n - 1} = 46

2^{300} + 2^{300} = 2^{x}

4 \cdot 3^{2 x} = 5^{x}

What is the answer to 7^{x+6}=3^x ?
The answer to 7^{x+6}=3^x is x=-(6ln(7))/(ln(7)-ln(3))
Solve for x: 7^{x+6}=3^x
The solution is x=-(6ln(7))/(ln(7)-ln(3))