What is the answer to 10^{7x+35}=10^{2x+5} ?

The answer to 10^{7x+35}=10^{2x+5} is x=-6

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10^{7x+35}=10^{2x+5}

1 0^{7 x + 35} = 1 0^{2 x + 5}

x = - 6

Solution steps

1 0^{7 x + 35} = 1 0^{2 x + 5}

Apply exponent rules

7 x + 35 = 2 x + 5

Solve

7 x + 35 = 2 x + 5 : x = - 6

x = - 6

3 6^{3 x + 1} = 121

2^{3 x - 4} = 3

2^{3 x - 4} = 5

3^{x} - 3^{x - 1} + 3^{x - 2} = 21

e^{(2 t + 1)} = 9 e^{(1 - t)}

What is the answer to 10^{7x+35}=10^{2x+5} ?
The answer to 10^{7x+35}=10^{2x+5} is x=-6
Solve for x: 10^{7x+35}=10^{2x+5}
The solution is x=-6