What is the answer to 2^{3x-4}=5 ?

The answer to 2^{3x-4}=5 is x=(ln(80))/(3ln(2))

Solve for x: 2^{3x-4}=5

The solution is x=(ln(80))/(3ln(2))

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2^{3 x - 4} = 5

x = \frac{ln ( 80 )}{3 ln ( 2 )}

Solution steps

2^{3 x - 4} = 5

Apply exponent rules

(3 x - 4) ln (2) = ln (5)

Solve

(3 x - 4) ln (2) = ln (5) : x = \frac{ln ( 80 )}{3 ln ( 2 )}

x = \frac{ln ( 80 )}{3 ln ( 2 )}

3^{x} - 3^{x - 1} + 3^{x - 2} = 21

e^{(2 t + 1)} = 9 e^{(1 - t)}

x, 2 e^{3 x} = 4 e^{5 x}

5^{x - 3} = 10

x, 2^{x} - 2^{y} = 128

What is the answer to 2^{3x-4}=5 ?
The answer to 2^{3x-4}=5 is x=(ln(80))/(3ln(2))
Solve for x: 2^{3x-4}=5
The solution is x=(ln(80))/(3ln(2))