What is the answer to solvefor x,2e^{3x}=4e^{5x} ?

The answer to solvefor x,2e^{3x}=4e^{5x} is x=-(ln(2))/2

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solvefor x,2e^{3x}=4e^{5x}

solve for

x, 2 e^{3 x} = 4 e^{5 x}

x = - \frac{ln ( 2 )}{2}

Solution steps

2 e^{3 x} = 4 e^{5 x}

Apply exponent rules

ln (2) + 3 x = ln (4) + 5 x

Solve

ln (2) + 3 x = ln (4) + 5 x : x = - \frac{ln ( 2 )}{2}

x = - \frac{ln ( 2 )}{2}

5^{x - 3} = 10

x, 2^{x} - 2^{y} = 128

6 = 12 \cdot 5^{- k^{20}}

7^{- x} \cdot 7^{- x} = 343

0 = 10 e^{0.002 x}

What is the answer to solvefor x,2e^{3x}=4e^{5x} ?
The answer to solvefor x,2e^{3x}=4e^{5x} is x=-(ln(2))/2