What is the answer to 3^{4x+1}*9^{x-1}=81 ?

The answer to 3^{4x+1}*9^{x-1}=81 is x= 5/6

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3^{4x+1}*9^{x-1}=81

3^{4 x + 1} \cdot 9^{x - 1} = 81

x = \frac{5}{6}

Solution steps

3^{4 x + 1} \cdot 9^{x - 1} = 81

Apply exponent rules

4 x + 1 + 2 (x - 1) = 4

Solve

4 x + 1 + 2 (x - 1) = 4 : x = \frac{5}{6}

x = \frac{5}{6}

x e^{- x} = - 3 (x e^{- x}) + 1

(6) (8^{x}) = 2 e^{3 x}

A (x) = 500 (1.03)^{x}

4 9^{x + 3} = 7^{x^{2} - 3 x + 8}

8^{x} = 360000000

What is the answer to 3^{4x+1}*9^{x-1}=81 ?
The answer to 3^{4x+1}*9^{x-1}=81 is x= 5/6
Solve for x: 3^{4x+1}*9^{x-1}=81
The solution is x= 5/6