What is the answer to 8^{x-1}=125 ?

The answer to 8^{x-1}=125 is x=(ln(5))/(ln(2))+1

Solve for x: 8^{x-1}=125

The solution is x=(ln(5))/(ln(2))+1

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8^{x - 1} = 125

x = \frac{ln ( 5 )}{ln ( 2 )} + 1

Solution steps

8^{x - 1} = 125

Apply exponent rules

(x - 1) ln (8) = ln (125)

Solve

(x - 1) ln (8) = ln (125) : x = \frac{ln ( 5 )}{ln ( 2 )} + 1

x = \frac{ln ( 5 )}{ln ( 2 )} + 1

(\frac{1}{7})^{x} = \frac{1}{49}

51 = 4 e^{3 x}

69 = 2 5^{x}

2^{x} = e^{x l n (2)}

\frac{4}{( 2 ^{x} )} = 98

What is the answer to 8^{x-1}=125 ?
The answer to 8^{x-1}=125 is x=(ln(5))/(ln(2))+1
Solve for x: 8^{x-1}=125
The solution is x=(ln(5))/(ln(2))+1