What is the answer to 2^{3x}-2^{7x-2}=0 ?

The answer to 2^{3x}-2^{7x-2}=0 is x= 1/2

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2^{3x}-2^{7x-2}=0

2^{3 x} - 2^{7 x - 2} = 0

x = \frac{1}{2}

Solution steps

2^{3 x} - 2^{7 x - 2} = 0

Add

2^{7 x - 2}

to both sides

2^{3 x} - 2^{7 x - 2} + 2^{7 x - 2} = 0 + 2^{7 x - 2}

Simplify

2^{3 x} = 2^{7 x - 2}

Apply exponent rules

3 x = 7 x - 2

Solve

3 x = 7 x - 2 : x = \frac{1}{2}

x = \frac{1}{2}

- 5 \cdot 7^{- 3 x - 6} - 8 = - 9

4 = 3^{x - 3}

x, 1 - e^{- x^{4}} = r

8^{x} = 51 2^{x + 2}

y, x = 2 y + 4^{y}

What is the answer to 2^{3x}-2^{7x-2}=0 ?
The answer to 2^{3x}-2^{7x-2}=0 is x= 1/2
Solve for x: 2^{3x}-2^{7x-2}=0
The solution is x= 1/2