What is the answer to solvefor x,1-e^{-x^4}=r ?

The answer to solvefor x,1-e^{-x^4}=r is x=\sqrt[4]{-ln(-r+1)},x=-\sqrt[4]{-ln(-r+1)}

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solvefor x,1-e^{-x^4}=r

solve for

x, 1 - e^{- x^{4}} = r

Solution steps

1 - e^{- x^{4}} = r

Move

1

to the right side

- e^{- x^{4}} = r - 1

Divide both sides by

- 1

e^{- x^{4}} = - r + 1

Apply exponent rules

- x^{4} = ln (- r + 1)

Solve

8^{x} = 51 2^{x + 2}

y, x = 2 y + 4^{y}

2^{x + 1} = 3^{x - 5}

2. 2^{x} = 8

3^{x^{2}} = 9^{- x + 12}

What is the answer to solvefor x,1-e^{-x^4}=r ?
The answer to solvefor x,1-e^{-x^4}=r is x=\sqrt[4]{-ln(-r+1)},x=-\sqrt[4]{-ln(-r+1)}