What is the answer to 2^{x+1}=3^{x-5} ?

The answer to 2^{x+1}=3^{x-5} is x=(ln(486))/(ln(3)-ln(2))

Solve for x: 2^{x+1}=3^{x-5}

The solution is x=(ln(486))/(ln(3)-ln(2))

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2^{x + 1} = 3^{x - 5}

x = \frac{ln ( 486 )}{ln ( 3 ) - ln ( 2 )}

Solution steps

2^{x + 1} = 3^{x - 5}

Apply exponent rules

(x + 1) ln (2) = (x - 5) ln (3)

Solve

(x + 1) ln (2) = (x - 5) ln (3) : x = \frac{ln ( 486 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 486 )}{ln ( 3 ) - ln ( 2 )}

2. 2^{x} = 8

3^{x^{2}} = 9^{- x + 12}

3^{- x} = \frac{1}{3 ^{x}}

4^{2 x} - 68 \cdot 4^{x} + 256 = 0

x, 4^{3 x} = 4^{x - 1}

What is the answer to 2^{x+1}=3^{x-5} ?
The answer to 2^{x+1}=3^{x-5} is x=(ln(486))/(ln(3)-ln(2))
Solve for x: 2^{x+1}=3^{x-5}
The solution is x=(ln(486))/(ln(3)-ln(2))