What is the answer to 2^x-1=100 ?

The answer to 2^x-1=100 is x=(ln(101))/(ln(2))

Solve for x: 2^x-1=100

The solution is x=(ln(101))/(ln(2))

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2^{x} - 1 = 100

x = \frac{ln ( 101 )}{ln ( 2 )}

Solution steps

2^{x} - 1 = 100

Move

1

to the right side

2^{x} = 101

Apply exponent rules

x ln (2) = ln (101)

Solve

x ln (2) = ln (101) : x = \frac{ln ( 101 )}{ln ( 2 )}

x = \frac{ln ( 101 )}{ln ( 2 )}

x, 7 e^{1 x + 2.3} = 136

2^{x} = e^{x + 2}

37.5 = 3^{n}

3^{- 2 b} = \frac{1}{27}

4^{2 x} - 2 (4^{x}) - 8 = 0

What is the answer to 2^x-1=100 ?
The answer to 2^x-1=100 is x=(ln(101))/(ln(2))
Solve for x: 2^x-1=100
The solution is x=(ln(101))/(ln(2))