What is the answer to 3^{2x-6}= 1/(9^{x+1)} ?

The answer to 3^{2x-6}= 1/(9^{x+1)} is x=1

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3^{2x-6}= 1/(9^{x+1)}

3^{2 x - 6} = \frac{1}{9 ^{x + 1}}

x = 1

Solution steps

3^{2 x - 6} = \frac{1}{9 ^{x + 1}}

Apply exponent rules

2 x - 6 = 2 (- x - 1)

Solve

2 x - 6 = 2 (- x - 1) : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

1100 = 250 \cdot 2^{\frac{1}{t}}

10 = 200 e^{- 0.347 x}

m e^{m x} + 3 e^{m x} = 0

22 = 200 \cdot (0.8)^{t}

4^{x + 1} \cdot (- 1) = - 4^{x + 1}

What is the answer to 3^{2x-6}= 1/(9^{x+1)} ?
The answer to 3^{2x-6}= 1/(9^{x+1)} is x=1
Solve for x: 3^{2x-6}= 1/(9^{x+1)}
The solution is x=1